x^2-300x+2=0

Solution for x^2-300x+2=0 equation:

x^2-300x+2=0

a = 1; b = -300; c = +2;
Δ = b2-4ac
Δ = -3002-4·1·2
Δ = 89992
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{89992}=\sqrt{4*22498}=\sqrt{4}*\sqrt{22498}=2\sqrt{22498}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-300)-2\sqrt{22498}}{2*1}=\frac{300-2\sqrt{22498}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-300)+2\sqrt{22498}}{2*1}=\frac{300+2\sqrt{22498}}{2}
$